Answer
Reaction 1: 628 kJ
Reaction 2: 587 kJ
Work Step by Step
We add up the enthalpies of the reactants for both reactions:
$\Delta H_1 = 436+192=628 KJ$
$\Delta H_2 = 436+`151=587 KJ$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 4 - Energy and Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 189d: 62a
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