Answer
$132\,J\,mol^{-1}K^{-1}$
Work Step by Step
Molar heat capacity=
$0.861\,J\,g^{-1}K^{-1}\times \frac{153.82\,g\,CCl_{4}}{1\,mol\,CCl_{4}}$
$= 132\,J\,mol^{-1}K^{-1}$
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