Answer
$ 2FeS_{2} + 15O_{2} + 14H_{2}O → 4Fe(OH)^{3} + 8H_{2}(SO_{4})_{2}$
Work Step by Step
In the presence of oxygen, water, and a sufficiently high hydroxide ion concentration, Iron (II) Sulfide forms iron(III) hydroxide and sulfuric acid. The reaction is given above. Recall, in order to consider the reaction, it is necessary to be sure that the same number of each of the elements that are on the reactants side of the reaction are also on the products side of the reaction.
