Answer
- This is a precipitation reaction.
Products:
$ZnCO_3$
$2NaCl$
Completed equation:
$ZnCl_2(aq) + Na_2CO_3(aq) \lt -- \gt ZnCO_3(s) + 2NaCl(aq)$
Work Step by Step
1. Write and analyze the products of the reaction:
- Since we have 2 ionic compounds, we will have a double displacement reaction. So, the products are:
$ZnCO_3$: Which is insoluble in water*
$Na_2Cl_2 --> 2NaCl$: Which is soluble in water*
* According to table 3.1 (Page 101).
Since we have an insoluble product, there will be precipitation.
- This is a precipitation reaction.
Since we already have the reactants and the products, the final chemical reaction is:
$ZnCl_2(aq) + Na_2CO_3(aq) \lt -- \gt ZnCO_3(s) + 2NaCl(aq)$
- The reaction is balanced.
