Answer
$Cu$ is the identity of the metal, because it gives exactly 0.376 g of carbon dioxide.
Work Step by Step
1. Calculate the number of moles of $CuCO_3$:
63.55* 1 + 12.01* 1 + 16* 3 = 123.56g/mol
$1.056g \times \frac{1 mol}{ 123.56g} = 8.546 \times 10^{-3}mol (CuCO_3)$
- The balanced reaction is:
$CuCO_3 -- \gt CuO + CO_2$
The ratio of $CuCO_3$ to $CO_2$ is 1 to 1:
$8.546 \times 10^{-3} mol (CuCO_3) \times \frac{ 1 mol(CO_2)}{ 1 mol (CuCO_3)} = 8.546 \times 10^{-3}mol (CO_2)$
2. Calculate the mass of $CO_2$:
12.01* 1 + 16* 2 = 44.01g/mol
$8.546 \times 10^{-3} mol \times \frac{ 44.01 g}{ 1 mol} = 0.376g (CO_2)$
