Chapter 3 - Chemical Reactions - Exercise 3.7 - Net Ionic Equations and Antacids - Page 112: a

$Al(OH)_{3}(s) + 3 H^{+}(aq) → 3 H_{2}O(ℓ) + Al^{3+}(aq)$

We know: $Al(OH)_{3}(s) + 3 H^{+}(aq) + 3 Cl^{−}(aq) → 3 H_{2}O(ℓ) + Al^{3+}(aq) + 3 Cl^{−}(aq)$ The net ionic equation is: $Al(OH)_{3}(s) + 3 H^{+}(aq) → 3 H_{2}O(ℓ) + Al^{3+}(aq)$