Answer
Complete ionic equation:
$H^+(aq) + Cl^-(aq) + K^+(aq) + OH^-(aq) -- \gt Cl^-(aq) + K^+(aq) + H_2O(l)$
Net ionic equation:
$H^+(aq) + OH^-(aq) -- \gt H_2O(l)$
Work Step by Step
1. Identify the salt produced by the mixture of this acid and this base.
$HCl$ gives $Cl^-$ after the reaction.
$KOH$ gives $K^+$ after the reaction.
Therefore, the salt formed is: $KCl$
2. Write the overall equation:
$Acid + Base --\gt Salt + Water$
$HCl(aq) + KOH(aq) -- \gt KCl(aq) + H_2O(l)$
* The equation is already balanced.
** According to table 3.1, KCl is soluble in water.
3. On the totally dissociated/ionized compounds, write the separate ions:
$H^+(aq) + Cl^-(aq) + K^+(aq) + OH^-(aq) -- \gt Cl^-(aq) + K^+(aq) + H_2O(l)$
** HCl is a strong acid, KOH is a strong base, and KCl is a soluble salt.
This is the complete ionic equation.
4. Remove the spectators ions:
$H^+(aq) + OH^-(aq) -- \gt H_2O(l)$
This is the net ionic equation.
