Answer
The molar mass for $Mn_2(SO_4)_3$ is equal to 398.09g/mol.
Work Step by Step
$Mn:$ 54.94* 2 +
$S{O_4}:$ 3 * ( 32.07($S$)* 1 + 16.00($O$)* 4 )
Adding these molar masses together gives:
398.09g/mol
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 2 - Chemical Compounds - Exercise 2.18 - Molar Masses - Page 80: c
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