Answer
$_{11}^{22}Na$
Work Step by Step
Na-22 undergoes positron emission to form Ne-22
$_{11}^{22}Na → _{10}^{22}Ne +_{+1}^{0}e$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 18 - Nuclear Chemistry - Questions for Review and Thought - Topical Questions - Page 817a: 15a
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