Answer
$V^{2+}$
Work Step by Step
If the value of $E^{\circ}$ is more negative, it means that the strength of the oxidizing agent is less. Therefore, $V^{2+}$ with the most negative $E^{\circ}$ value is the weakest oxidizing agent.
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 17 - Electrochemistry and Its Applications - Conceptual Exercise 17.9 - Predicting Redox Reactions Using E(o) Values - Page 759: a
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