Answer
113.0 J/K
Work Step by Step
For the vaporization reaction
$CH_{3}OH(l)\rightarrow CH_{3}OH(g)$
$\Delta _{r}S^{\circ}=\Sigma n_{p}S^{\circ}(products)-\Sigma n_{r}S^{\circ}(reactants)$
$=[1\,mol\times S^{\circ}(CH_{3}OH,g)]-[1\,mol\times S^{\circ}(CH_{3}OH,l)]$
$=1\,mol\times239.8\,Jmol^{-1}K^{-1}-1\,mol\times126.8\,Jmol^{-1}K^{-1}$
$=113.0\,J/K$
