Answer
Reactant-favored;
Minimum work required=$514.382\,kJ/mol$
Work Step by Step
$\Delta_{r}G^{\circ}=\Sigma n_{p}\Delta_{f}G^{\circ}(products)-\Sigma n_{r}\Delta_{f}G^{\circ}(reactants)$
$=[2\Delta_{f}G^{\circ}(CO,g)+\Delta_{f}G^{\circ}(O_{2},g)]-[2\Delta_{f}G^{\circ}(CO_{2},g)]$
$=[2(-137.168\,kJ/mol)+(0\,kJ/mol)]-[2(-394.359\,kJ/mol)]$
$=514.382\,kJ/mol$
$\Delta_{r}G^{\circ}$ is positive. Therefore, the reaction is reactant-favored.
Minimum work required= $514.382\,kJ/mol$
