Answer
$K_{sp} = [Sr^{2+}][S{O_4}^{2-}]$
Work Step by Step
1. Identify the ions, and write the equilibrium reaction for the dissociation of the salt $(SrSO_4)$:
- $Sr^{2+}$ and $S{O_4}^{2-}$
- $SrSO_4(s) \lt -- \gt Sr^{2+}(aq) + S{O_4}^{2-}(aq)$
2. Balance the reaction:
- $1 SrSO_4(s) \lt -- \gt 1Sr^{2+}(aq) + 1S{O_4}^{2-}(aq)$
3. Write the $K_{sp}$ expression:
- Multiply the concentrations of the ions.
- The balancing coefficients are used to determine the exponents of the concentrations.
- $K_{sp} = [Sr^{2+}]^1 \times [S{O_4}^{2-}]^1$
