Answer
$ K_{sp} (Ag_2C_2O_4) = (1.4 \times 10^{-12})$
Work Step by Step
1. Write the $K_{sp}$ expression:
$ Ag_2C_2O_4(s) \lt -- \gt 2Ag^{+}(aq) + 1C_2{O_4}^{2-}(aq)$
$ K_{sp} = [Ag^{+}]^ 2[C_2{O_4}^{2-}]^ 1$
2. Determine the ion concentrations:
$[Ag_2C_2O_4] * 1 = [C_2{O_4}^{2-}] = 6.9 \times 10^{-5}$
$[Ag^{+}] = [Ag_2C_2O_4] * 2 = [6.9 \times 10^{-5}] * 2 = 1.4 \times 10^{-4}$
3. Calculate the $K_{sp}$:
$ K_{sp} = (1.4 \times 10^{-4})^ 2 \times (6.9 \times 10^{-5})^ 1$
$ K_{sp} = (2.0 \times 10^{-8}) \times (6.9 \times 10^{-5})$
$ K_{sp} = (1.4 \times 10^{-12})$
