Answer
$NH_3CH_3COOH^+(aq) + H_2O(l) \lt -- \gt NH_3CH_3COO(aq) + H_3O^+(aq)$
$NH_3CH_3COO(aq) + H_2O(l) \lt -- \gt NH_2CH_3COO^-(aq) + H_3O^+(aq)$
Work Step by Step
1. Identify if the compound is a polyprotic acid or base:
- $NH_3CH_3COOH^+$ is an acid.
2. Write the ionization equation for the original acid.
- Write an equation where $NH_3CH_3COOH^+$ donates a proton to a water molecule.
3. Now, for polyprotic acids, the conjugate base is capable of donating one proton too, so write an equation where it does that.
- $NH_3CH_3COO$ can act as an acid too, so write an equation where it donates a proton to a water molecule.
- Repeat "Step 3" for the next reaction, until the conjugate base is incapable of donating one proton.
