Answer
$HS{O_4}^-(aq) + H_2O(l) \lt -- \gt H_2S{O_4}(aq) + OH^-(aq)$
Work Step by Step
- Acting as a base in water: Receiving one proton from the water.
- So, we need to write an equation where $HS{O_4}^-$ receives a proton, and the water loses one.
- $HS{O_4}^-(aq) + H_2O(l) \lt -- \gt H_2S{O_4}(aq) + OH^-(aq)$
