Answer
The reaction is not at equilibrium.
Work Step by Step
We calculate the value of Q to find:
$Q = \frac{(.0042)^2}{(.25)(.25)}=2.8\times10^{-4}$
This is not the value of k, so the reaction is not at equilibrium.
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 12 - Chemical Equilibrium - Questions for Review and Thought - Topical Questions - Page 563e: 60a
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