Answer
$K_{p}$ = 1.6
Work Step by Step
$K_{c} = \frac{[H_{2}O][CO]}{[H_{2}][CO_{2}]} = \frac{(0.11)(0.11)}{(0.087)(0.087)} = 1.6$
$\Delta n = 2-2 = 0$
$K_{p} = K_{c}(RT)^{\Delta n} = K_{c}(RT)^{0} = K_{c}\times1$ = 1.6
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 12 - Chemical Equilibrium - Questions for Review and Thought - Topical Questions - Page 523b: 36
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