Answer
$$K_c = \frac{[HCN][OH^-]}{[CN^-]} $$
Work Step by Step
$$K_c = \frac{[Products]}{[Reactants]}$$
$$K_c = \frac{[HCN][OH^-]}{[CN^-]} $$
** Since $H_2O$ is a pure liquid, we do not put it in the equation for $K_c$.
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 12 - Chemical Equilibrium - Problem Solving Practice 12.1 - Page 531: d
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
