Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 11 - Chemical Kinetics: Rates of Reactions - Questions for Review and Thought - General Questions - Page 523h: 99a

Answer

$2.8\times10^{3} s$

Work Step by Step

$t_{\frac{1}{2}}=\frac{0.693}{k}=\frac{0.693}{2.5\times10^{-4}s^{-1}}=2.8\times10^{3}s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.