Answer
The correct answer is (b)
Work Step by Step
Before the reaction, the oxidation state of Na is 0, and +1 after the reaction. So, Na is oxidized. Hence, $H_2O$ is the oxidizing agent.
Chemistry: Molecular Approach (4th Edition)
by Tro, Nivaldo J.
Published by
Pearson
ISBN 10:
0134112830
ISBN 13:
978-0-13411-283-1
Chapter 4 - Self-Assessment Quiz - Page 183: Q14
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