Answer
22 kg
Work Step by Step
** 1 kg = 1000g
$16kg \times \frac{1000g}{1kg} = 16 \times 10^{3}g$
1. Calculate the number of moles of $NO_2$:
14.01* 1 + 16* 2 = 46.01g/mol
$16\times 10^{3}g \times \frac{1 mol}{ 46.01g} = 347.8mol (NO_2)$
According to the balanced equation:
The ratio of $NO_2$ to $HNO_3$ is 4 to 4:
$347.8 mol (NO_2) \times \frac{ 4 mol(HNO_3)}{ 4 mol (NO_2)} = 347.8mol (HNO_3)$
2. Calculate the mass of $HNO_3$:
1.008* 1 + 14.01* 1 + 16* 3 = 63.02g/mol
$347.8 mol \times \frac{ 63.02 g}{ 1 mol} = 2.2\times 10^{4}g (HNO_3)$
$2.2 \times 10^4 g \times \frac{1kg}{1000g} = 22kg$
