Answer
(b) $5.3 \times 10^{-6} \space M$
Work Step by Step
We find:
$$[OH^-] = \frac{1.0 \times 10^{-14}}{[H_3O^+]} = \frac{1.0 \times 10^{-14}}{ 1.9 \times 10^{-9} } = 5.3 \times 10^{-6} \space M$$
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