Answer
(a) $O_{2}$ being a product,the reaction shifts toward right side.
(b) $KCl(s)$ will have no effect on equilibrium.
(c) $KClO_3(s)$ will have no effect on the equilibrium
(d) $O_2$ being a product,the reaction shifts toward left side.
Work Step by Step
(a) According to Le Chatelier's Principle, when a product is removed from equilibrium mixture the reaction moves toward right side(products).
(b) As $KCl(s)$ is a solid and therefore it does not affects the equilibrium and the equilibrium will remain unchanged.
(c) As $KClO_3(s)$ is a solid and therefore it does not affects the equilibrium and the equilibrium will remain unchanged.
(d) According to Le Chatelier's Principle,if a product is added to equilibrium mixture then the reaction will moves toward left side(reactant).
