Answer
26.1 atm
Work Step by Step
Molarity $M=\frac{\text{Moles of glycerin}}{\text{Volume of solution in L}}$
$=\frac{\frac{24.6\,g}{92.09382\,g/mol}}{250.0\times10^{-3}\,L}$
$=1.0684756\,M$
Osmotic pressure $\Pi=MRT$
$=(1.0684756\,M)(0.08206\,L\,atm\,K^{-1}mol^{-1})(298\,K)$
$=26.1\,atm$
