Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 1 - Exercises - Page 41: 125

Answer

\[\underline{6.8\times {{10}^{-15}}}\]

Work Step by Step

Radius of hydrogen atom is \[52.9\text{ pm}\]. \[\text{1 pm}=\text{1}{{\text{0}}^{-10}}\text{ cm}\] Thus, radius of hydrogen atom in centimeters is written as follows: \[r=52.9\times {{10}^{-10}}\text{ cm}\] Now, volume of an atom (sphere) is as follows: \[V=\frac{4}{3}\pi {{r}^{3}}\] Thus, \[V=\frac{4}{3}\pi {{\left( 52.9\times {{10}^{-10}}\text{ cm} \right)}^{3}}\] Radius of proton is \[1.0\times {{10}^{-13}}cm\]. Thus, volume of a proton is as follows: \[V=\frac{4}{3}\pi {{\left( 1.0\times {{10}^{-13}}\ \text{cm} \right)}^{3}}\] Now, fraction of the space within the atom occupied by the nucleus is as follows: \[\begin{align} & F=\frac{\frac{4}{3}\pi {{\left( 1.0\times {{10}^{-13}}\ \text{cm} \right)}^{3}}}{\frac{4}{3}\pi {{\left( 52.9\times {{10}^{-10}}\text{ cm} \right)}^{3}}} \\ & =6.8\times {{10}^{-15}} \end{align}\] The fraction of the space within the atom occupied by the nucleus is \[\underline{6.8\times {{10}^{-15}}}\].
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