Answer
$[OH^-] = 1.82\times 10^{- 6}M$
$[H_3O^+] = 5.495\times 10^{- 9}M$
pH = 8.26
- The solution is basic.
Work Step by Step
1. Calculate the hydroxide concentration:
$[OH^-] = 10^{-pOH}$
$[OH^-] = 10^{- 5.74}$
$[OH^-] = 1.82 \times 10^{- 6}$
2. Calculate the pH, then the hydronium concentration:
pOH + pH = 14
5.74 + pH = 14
pH = 8.26
$[H_3O^+] = 10^{- 8.26}$
$[H_3O^+] = 5.495 \times 10^{- 9}$
- Since $[OH^-] > [H_3O^+]$, this solution is basic.
