Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Let's Review: The Tools of Quantitative Chemistry - Study Questions - Page 43c: 32

Answer

$n=1.63$

Work Step by Step

Solving for n: $n=\frac{2.34\times15.6}{0.0821\times273}$ All numbers have three significant figures, so the answer must as well: $n=1.63$
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