Answer
See the answer below.
Work Step by Step
$F.\ Charge= NVE-LPE-BE/2$
a) N: $5-0-4/2=+3$
O: $6-6-2/2=-1$
b) N: $5-2-4/2=+1$
O: $6-6-2/2=-1$
c) N: $5-2-6/2=0$
F: $7-6-2/2=0$
d) N: $5-0-8/2=+1$
O(H): $6-4-4/2=0$
H: $1-0-2/2=0$
O(=): $6-4-4/2=0$
O(-): $6-6-2/2=-1$
These two O display ressonance, so their charge is -1/2.
