Answer
See the answer below.
Work Step by Step
Energy required by the atom is the same as the one provided by the photon:
$E=h\times\nu$
$3.3\times 10^{-19}\ J=6.626\times10^{-34}\ J.s\times \nu$
$\nu=4.98\times10^{14}\ 1/s$
$c=\lambda\times\nu$
$\lambda=2.998\times10^8\ m/s\div4.98\times10^{14}\ 1/s$
$\lambda=6.02\times10^{-7}\ m=602\ nm$
This is in the visible spectrum with a reddish color.
