Answer
$275.6\ kJ/mol$
Work Step by Step
$\lambda=434.1\ nm=0.4341\times10^{-6}\ m$
$c=\lambda\times\nu$
$\nu=6.91\times10^{14}\ s^{-1}$
Per photon:
$E=h\times\nu$
$E=4.58\times10^{-19}\ J$
Per mole:
$4.58\times10^{-19}\ J\times6.022\times10^{23}=275.6\ kJ/mol$