Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 6 The Structure of Atoms - 6-7 One More Electron Property: Electron Spin - Applying Chemical Principles - Page 244: 4

Answer

$275.6\ kJ/mol$

Work Step by Step

$\lambda=434.1\ nm=0.4341\times10^{-6}\ m$ $c=\lambda\times\nu$ $\nu=6.91\times10^{14}\ s^{-1}$ Per photon: $E=h\times\nu$ $E=4.58\times10^{-19}\ J$ Per mole: $4.58\times10^{-19}\ J\times6.022\times10^{23}=275.6\ kJ/mol$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.