Answer
See answer below.
Work Step by Step
Enthalpies of formation (kJ/mol):
$H_2O(g):-241.83, CO_2(g):-393.509$
Hydrazine:
$(2\times-241.83-50.6)\div 32.05\ g/mol=-16.66\ kJ/mol$
Dimethyl hydrazine:
$(2\times-393.509+4\times-241.83-48.9)\div 60.10\ g/mol=-30.00\ kJ/mol$
1,1-dimethylhydrazine produces more energy per unit of mass in combustion.