Answer
See answer below.
Work Step by Step
1: Zn is in excess,
$7.00\ g\div 65.38\ g/mol=0.107\ mol$
Ratio: $0.100/0.107=0.934\lt2$
2: Zn is in stoichiometric amount,
$3.27\ g\div 65.38\ g/mol=0.050\ mol$
Ratio: $0.100/0.050=2.00=2$
3: Zn is the limiting reactant,
$1.31\ g\div 65.38\ g/mol=0.020\ mol$
Ratio: $0.100/0.020=5.00\gt2$