Answer
See answer below.
Work Step by Step
a) Carbon dioxide and water
b) $C_6H_6+15/2\ O_2\rightarrow 6\ CO_2+3\ H_2O$
c) Number of moles of benzene:
$16.04\ g\div 78.11\ g/mol=0.2053\ mol$
From stoichiometry:
$1.540\ mol\ O_2$
Mass:
$1.540\ mol\times 32.00\ g/mol=49.28\ g$
d) The same mass as the reactants:
$16.04+49.28=65.32\ g$
