Answer
$107.5\ g$
Work Step by Step
Percent yield:
$37\%=15\ g/T.Y. \times 100\%$
$T.Y.= 40.54\ g$
Number of moles of hydrogen:
$40.54\ g/2.016\ g/mol=20.11\ mol$
From stoichiometry:
$20.11\ mol\times 1_{CH_4}/3_{H_2}\times 16.04\ g/mol=107.5\ g$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179c: 23
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