Answer
Sulfur is the limiting reactant.
$67.5\ g\ S_2Cl_2$
$35.54\ g\ Cl_2$
Work Step by Step
Number of moles of the reactants:
Sulfur: $32.0\ g\div 256.52\ g/mol=0.125\ mol$
Chlorine: $71.0\ g\div 70.91\ g/mol=1.00\ mol$
Ratio: $1.00/0.125=8.00$
Sulfur is the limiting reactant.
From stoichiometry:
$0.125\ mol\times 4_{S_2Cl_2}/1_{S_8} \times 135.04\ g/mol\ S_2Cl_2=67.5\ g\ S_2Cl_2$
Chlorine reacted:
$0.125\ mol\times 4_{Cl_2}/1_{S_8} \times 70.91\ g/mol\ Cl_2=35.46\ g\ Cl_2$
Remaining: $71.0-35.46=35.54\ g$
