Answer
See answer below.
Work Step by Step
a) $Ca(OH)_2$ is insoluble, remaining as a solid while the other compound would be solvated.
b) $MgF_2$ is insoluble, remaining as a solid while the other compound would be solvated.
c) $AgI$ is insoluble, remaining as a solid while the other compound would be solvated.
d) $PbCl_2$ is insoluble, remaining as a solid while the other compound would be solvated.