Answer
See answer below.
Work Step by Step
a) $2\ NaOH(aq)+FeCl_2(aq)\rightarrow Fe(OH)_2(s)+2\ NaCl(aq)$
Net ionic: $2\ OH^-(aq)+Fe^{2+}(aq)\rightarrow
Fe(OH)_2(s)$
b) $Na_2CO_3(aq)+BaCl_2(aq)\rightarrow BaCO_3(s)+2\ NaCl(aq)$
Net ionic: $CO_3^{2-}(aq)+Ba^{2+}(aq)\rightarrow BaCO_3(s)$
c) $3\ NH_3(aq)+H_3PO_4(aq)\rightarrow (NH_4)_3PO_4(aq)$
Net ionic: $NH_3(aq)+H_3O^{+}(aq) \rightarrow NH_4^+(aq)+H_2O(l)$
