Answer
a) $SF_{4} +2H_{2}O → SO_{2} + 4HF$
sulfer tetra chloride + water → sulfer dioxide + flouric acid
b) $4NH_{3} + 5 O_{2} → 4NO + 6H_{2}O$
ammoniua + oxygen → nitrous oxide + water
c) $BF_{3} + 3H_{2}O → 3HF + H_{3}BO_{3}$
boron tri fluoride + water → flouric acid+ boric acid
Work Step by Step
a) $SF_{4} +2H_{2}O → SO_{2} + 4HF$
sulfer tetra chloride + water → sulfer dioxide + flouric acid
b) $2NH_{3} + 5/2 O_{2} → 2NO + 3H_{2}O$
ammoniua + oxygen → nitrous oxide + water
c) $BF_{3} + 3H_{2}O → 3HF + H_{3}BO_{3}$
boron tri fluoride + water → flouric acid+ boric acid
