Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95k: 160

D

In 100 g: C: $54\ g\div 12.011\ g/mol=4.496\ mol$ H: $6.00\ g\div 1.008\ g/mol=5.952\ mol$ O: $40.0\ g\div 12.011\ g/mol=2.500\ mol$ C/O ratio: $4.496/2.500=1.80=9/5$ H/O ratio: $5.952/2.500=2.40=12/5$ Empirical formula: $C_9H_{12}O_5$