Answer
See the answer below.
Work Step by Step
Mass required:
$0.125\ mol\times 22.9898\ g/mol=2.87\ g$
Volume:
$2.87\ g\div 0.97\ g/cm^3=2.96\ cm^3$
In a perfect cube, the side would have:
$\sqrt[3]{2.96\ cm^3}=1.43\ cm$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95j: 153
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
