Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95e: 87

Answer

Empirical formula $CH$ Molecular formula: $C_2H_2$

Work Step by Step

Atomic weights (g/mol): $C: 12.011,\ H: 1.008$ In 100.0 g: C: $92.26\ g \div 12.011 = 7.68\ mol$ H: $7.74\ g\div 1.008 = 7.68\ mol$ Normalizing by the smallest amount of moles: C,H: $7.68/7.68 = 1.0$ Empirical formula $CH$ Empirical formula's molar mass: $M_u=13.02\ g/mol$ $M/M_u=2.0$ Molecular formula: $C_2H_2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.