Answer
Empirical formula $CH$
Molecular formula: $C_2H_2$
Work Step by Step
Atomic weights (g/mol): $C: 12.011,\ H: 1.008$
In 100.0 g:
C: $92.26\ g \div 12.011 = 7.68\ mol$
H: $7.74\ g\div 1.008 = 7.68\ mol$
Normalizing by the smallest amount of moles:
C,H: $7.68/7.68 = 1.0$
Empirical formula $CH$
Empirical formula's molar mass: $M_u=13.02\ g/mol$
$M/M_u=2.0$
Molecular formula: $C_2H_2$