Answer
a) $1.53\ g$
b) $4.60\ g$
c) $4.59\ g$
d) $1.48\ g$
Work Step by Step
Atomic weights: $O: 15.999u,\ C: 12.011u,\ H:1.008u$
a) $C_3H_7OH$: $M = 3\times12.01 + 8\times1.008+15.999=60.10\ g/mol$
$0.0255\ mol \times 60.10\ g/mol = 1.53\ g$
b) $C_{11}H_{16}O_2$: $M = 11\times12.01 + 16\times1.008+2\times15.999=180.2\ g/mol$
$0.0255\ mol \times 180.2\ g/mol = 4.60\ g$
c) $C_9H_8O_4$: $M = 9\times12.01 + 8\times1.008+4\times15.999=180.2\ g/mol$
$0.0255\ mol \times 180.2\ g/mol = 4.59\ g$
d) $(CH_3)_2CO$: $M = 3\times12.01 + 6\times1.008+15.999=58.08\ g/mol$
$0.0255\ mol \times 58.08\ g/mol = 1.48\ g$
