Answer
a) $67\ g $
b) $0.0698\ g $
c) $0.60\ g $
d) $1.32\times10^4\ g $
Work Step by Step
Atomic weights: $Al: 26.982u,\ Fe: 55.845u,\ Ca: 40.078u,\ Ne: 20.180u$
a) $2.5\ mol \times 26.982\ g/mol = 67\ g $
b) $1.25\times10^{-3}\ mol \times 55.845\ g/mol = 0.0698\ g $
c) $0.015\ mol \times 40.078\ g/mol = 0.60\ g $
d) $653\ mol \times 20.180\ g/mol = 1.32\times10^4\ g $