Answer
A
Work Step by Step
The ion barium is $Ba^{2+}$, and acetate is $CH_3-COO^-$, so:
$Ba(CH_3CO_2)_2$
Note that there are 2 acetate molecules for every one Barium so that the charge will balance to 0.
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 2 Atoms, Molecules, and Ions - 2-7 Ionic Compounds: Formulas, Names, and Properties - Review & Check for Section 2-7 - Page 75: 4
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
