Answer
B
Work Step by Step
Atomic weights: $C: 12.011\ g/mol,\ H:1.008\ g/mol,\ O:15.999\ g/mol$
Empirical formula's weight: $M_u=12.011+2\times1.008+15.999=30.026\ g/mol$
For a molecular mass of 180 g/mol: $M/M_u=180/30.026=6.0$
$C_6H_{12}O_6$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 2 Atoms, Molecules, and Ions - 2-10 Chemical Analysis: Determining Compound Formulas - Review & Check for Section 2-10 - Page 93: 2
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