Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677d: 83

$Ag_2CO_3 < BaCO_3 < Na_2CO_3$

Na2CO3 is soluble in water Ksp of BaCO3 $2.58\dot{}10^{-9}$ Ksp of Ag2CO3 $8.46\dot{}10^{-12}$ Increasing solubility: $Ag_2CO_3 < BaCO_3 < Na_2CO_3$ Note: BaCO3 has two ions in solution so $Ksp = s^2$ and Ag2CO3 has three so $Ksp = 4s^3$, but since the Ksp of BaCO3 is higher calculating the solubility directly isn't necessary.