Answer
$ K_{sp} = (3.6 \times 10^{-6}) $
Work Step by Step
1. Write the $K_{sp}$ expression:
$ TlBr(s) \lt -- \gt 1Tl^{+}(aq) + 1Br^{-}(aq)$
$ K_{sp} = [Tl^{+}]^ 1[Br^{-}]^ 1$
2. Calculate the $K_{sp}$:
$ K_{sp} = (1.9 \times 10^{-3}) \times (1.9 \times 10^{-3})$
$ K_{sp} = (3.6 \times 10^{-6})$