Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677b: 43

Answer

$ K_{sp} = (3.6 \times 10^{-6}) $

Work Step by Step

1. Write the $K_{sp}$ expression: $ TlBr(s) \lt -- \gt 1Tl^{+}(aq) + 1Br^{-}(aq)$ $ K_{sp} = [Tl^{+}]^ 1[Br^{-}]^ 1$ 2. Calculate the $K_{sp}$: $ K_{sp} = (1.9 \times 10^{-3}) \times (1.9 \times 10^{-3})$ $ K_{sp} = (3.6 \times 10^{-6})$
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