Answer
See the answer below.
Work Step by Step
$K_a=[H_3O^+][NH_3]/[NH_4^+]$
Applying the -log to both sides
$pKa=pH-log([NH_3]/[NH_4^+])$
$[NH_3]/[NH_4^+]=1.77$
Mix them with a ratio of 1.77 mol of ammonia per mol of ammonium.
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677a: 20
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