Answer
$pH=2.68$
Work Step by Step
Molarity: $2\cdot 0.325\ g\div 180.16\ g/mol\div 0.225\ L=0.016\ M$
$K_a=[H_3O^+][A^-]/[HA]$
$3.27\cdot10^{-4}=x\cdot x/(0.016-x)$
$x=0.0021\ M$
$pH=-log([H_3O^+])$
$pH=2.68$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - Study Questions - Page 629e: 83
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